3x^2-6=432

Solution for 3x^2-6=432 equation:

3x^2-6=432

We move all terms to the left:

3x^2-6-(432)=0

We add all the numbers together, and all the variables

3x^2-438=0

a = 3; b = 0; c = -438;
Δ = b2-4ac
Δ = 02-4·3·(-438)
Δ = 5256
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{5256}=\sqrt{36*146}=\sqrt{36}*\sqrt{146}=6\sqrt{146}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-6\sqrt{146}}{2*3}=\frac{0-6\sqrt{146}}{6}
=-\frac{6\sqrt{146}}{6}
=-\sqrt{146}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+6\sqrt{146}}{2*3}=\frac{0+6\sqrt{146}}{6}
=\frac{6\sqrt{146}}{6}
=\sqrt{146}
$